f(n)=f(n-2)+2f

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Solution for f(n)=f(n-2)+2f equation:


Simplifying
f(n) = f(n + -2) + 2f

Multiply f * n
fn = f(n + -2) + 2f

Reorder the terms:
fn = f(-2 + n) + 2f
fn = (-2 * f + n * f) + 2f
fn = (-2f + fn) + 2f

Reorder the terms:
fn = -2f + 2f + fn

Combine like terms: -2f + 2f = 0
fn = 0 + fn
fn = fn

Add '-1fn' to each side of the equation.
fn + -1fn = fn + -1fn

Combine like terms: fn + -1fn = 0
0 = fn + -1fn

Combine like terms: fn + -1fn = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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