f(n+1)=3+2f(n)

Solution for f(n+1)=3+2f(n) equation:

Simplifying
f(n + 1) = 3 + 2f(n)

Reorder the terms:
f(1 + n) = 3 + 2f(n)
(1 * f + n * f) = 3 + 2f(n)
(1f + fn) = 3 + 2f(n)

Multiply f * n
1f + fn = 3 + 2fn

Solving
1f + fn = 3 + 2fn

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-2fn' to each side of the equation.
1f + fn + -2fn = 3 + 2fn + -2fn

Combine like terms: fn + -2fn = -1fn
1f + -1fn = 3 + 2fn + -2fn

Combine like terms: 2fn + -2fn = 0
1f + -1fn = 3 + 0
1f + -1fn = 3

Reorder the terms:
-3 + 1f + -1fn = 3 + -3

Combine like terms: 3 + -3 = 0
-3 + 1f + -1fn = 0

The solution to this equation could not be determined.