f(n+1)=f(n)+2

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Solution for f(n+1)=f(n)+2 equation:


Simplifying
f(n + 1) = f(n) + 2

Reorder the terms:
f(1 + n) = f(n) + 2
(1 * f + n * f) = f(n) + 2
(1f + fn) = f(n) + 2

Multiply f * n
1f + fn = fn + 2

Reorder the terms:
1f + fn = 2 + fn

Add '-1fn' to each side of the equation.
1f + fn + -1fn = 2 + fn + -1fn

Combine like terms: fn + -1fn = 0
1f + 0 = 2 + fn + -1fn
1f = 2 + fn + -1fn

Combine like terms: fn + -1fn = 0
1f = 2 + 0
1f = 2

Solving
1f = 2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by '1'.
f = 2

Simplifying
f = 2

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