f(x)=(2x-3)/5

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Solution for f(x)=(2x-3)/5 equation: 


1;6;3;17;11;8

1;7;2;9;3;4

64*x^3-(48*x)+0*x^2+11 = 0

3;4;2;5;2;1

1;4;1;16;0;0

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