f(x)=2sin(3x+1)-5

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Solution for f(x)=2sin(3x+1)-5 equation:


Simplifying
f(x) = 2sin(3x + 1) + -5

Multiply f * x
fx = 2sin(3x + 1) + -5

Reorder the terms:
fx = 2ins(1 + 3x) + -5
fx = (1 * 2ins + 3x * 2ins) + -5
fx = (2ins + 6insx) + -5

Reorder the terms:
fx = -5 + 2ins + 6insx

Solving
fx = -5 + 2ins + 6insx

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x'.
f = -5x-1 + 2insx-1 + 6ins

Simplifying
f = -5x-1 + 2insx-1 + 6ins

Reorder the terms:
f = 6ins + 2insx-1 + -5x-1

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