f(x+1)=4abs(x-2)

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Solution for f(x+1)=4abs(x-2) equation:


Simplifying
f(x + 1) = 4abs(x + -2)

Reorder the terms:
f(1 + x) = 4abs(x + -2)
(1 * f + x * f) = 4abs(x + -2)
(1f + fx) = 4abs(x + -2)

Reorder the terms:
1f + fx = 4abs(-2 + x)
1f + fx = (-2 * 4abs + x * 4abs)
1f + fx = (-8abs + 4absx)

Solving
1f + fx = -8abs + 4absx

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
8abs + -4absx + 1f + fx = -8abs + 4absx + 8abs + -4absx

Reorder the terms:
8abs + -4absx + 1f + fx = -8abs + 8abs + 4absx + -4absx

Combine like terms: -8abs + 8abs = 0
8abs + -4absx + 1f + fx = 0 + 4absx + -4absx
8abs + -4absx + 1f + fx = 4absx + -4absx

Combine like terms: 4absx + -4absx = 0
8abs + -4absx + 1f + fx = 0

The solution to this equation could not be determined.

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