f+30+2f=3(3f-2)

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Solution for f+30+2f=3(3f-2) equation: 



f+30+2f=3(3f-2)

We move all terms to the left:

f+30+2f-(3(3f-2))=0

We add all the numbers together, and all the variables

3f-(3(3f-2))+30=0



We calculate terms in parentheses: -(3(3f-2)), so:

3(3f-2)

We multiply parentheses

9f-6

Back to the equation:

-(9f-6)



We get rid of parentheses

3f-9f+6+30=0

We add all the numbers together, and all the variables

-6f+36=0

We move all terms containing f to the left, all other terms to the right

-6f=-36

f=-36/-6

f=+6

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