If it's not what You are looking for type in the equation solver your own equation and let us solve it.
((x+1)^(1/2))/(x^2)
8-4*x <= 5*x-3*x^2+2;x
x
35;144;6;35;0;0
7;18;15;24;0;0
6*(1/2) = 3*(2/3)
| k+45+k=-55+800 | | y-3=2(x-2) | | -3u+2=-10+30 | | -3u+2=10+30 | | F(x)=3x^3-ax^2-16x+3 | | 7y+7=4y-2 | | (2+4i)(-6-3i)= | | 8sin(x/2)-8=0 | | 6(1/2)=3(2/3) | | -7=w/2-5 | | (10b^2-b-3)(20b^2+12b)= | | 43t=387 | | 4w+8=15w-3+64 | | 1x-8-2x=4 | | f(3x)=x^2+2x-6 | | 1.4=-t/2.5 | | -5/3*(-1/8) | | 4w+8=15w-8+64 | | 12=6(2-4) | | -7/8*(-7/5) | | 5y+4y=3y+11 | | -7x-3=-7x-5 | | 4r-35=0 | | X+8whenx=6 | | 9+y=-7 | | -5=w-9 | | -14=-0.4k | | 4x^3-4x^2-3u+3=0 | | -8.4=0.12x | | b-5=-41 | | 7x-11y=21 | | =3ab/3abc |