f2-(4f-4f-8)=4f+4f-8

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Solution for f2-(4f-4f-8)=4f+4f-8 equation:



f2-(4f-4f-8)=4f+4f-8
We move all terms to the left:
f2-(4f-4f-8)-(4f+4f-8)=0
We add all the numbers together, and all the variables
f2-(8f-8)-(-8)=0
We add all the numbers together, and all the variables
f^2-(8f-8)+8=0
We get rid of parentheses
f^2-8f+8+8=0
We add all the numbers together, and all the variables
f^2-8f+16=0
a = 1; b = -8; c = +16;
Δ = b2-4ac
Δ = -82-4·1·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$f=\frac{-b}{2a}=\frac{8}{2}=4$

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