f2=0.36

Solution for f2=0.36 equation:

f2=0.36

We move all terms to the left:

f2-(0.36)=0

We add all the numbers together, and all the variables

f^2-0.36=0

a = 1; b = 0; c = -0.36;
Δ = b2-4ac
Δ = 02-4·1·(-0.36)
Δ = 1.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1.44}}{2*1}=\frac{0-\sqrt{1.44}}{2}
=-\frac{\sqrt{}}{2}
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1.44}}{2*1}=\frac{0+\sqrt{1.44}}{2}
=\frac{\sqrt{}}{2}
$