f2=196f

Solution for f2=196f equation:

f2=196f

We move all terms to the left:

f2-(196f)=0

We add all the numbers together, and all the variables

f^2-196f=0

a = 1; b = -196; c = 0;
Δ = b2-4ac
Δ = -1962-4·1·0
Δ = 38416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{38416}=196$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-196)-196}{2*1}=\frac{0}{2}
=0
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-196)+196}{2*1}=\frac{392}{2}
=196
$