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f2=2.3f=
We move all terms to the left:
f2-(2.3f)=0
We add all the numbers together, and all the variables
f2-(+2.3f)=0
We add all the numbers together, and all the variables
f^2-(+2.3f)=0
We get rid of parentheses
f^2-2.3f=0
a = 1; b = -2.3; c = 0;
Δ = b2-4ac
Δ = -2.32-4·1·0
Δ = 5.29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.3)-\sqrt{5.29}}{2*1}=\frac{2.3-\sqrt{5.29}}{2} $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.3)+\sqrt{5.29}}{2*1}=\frac{2.3+\sqrt{5.29}}{2} $
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