f=(9/5)(1)+32=

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Solution for f=(9/5)(1)+32= equation:



f=(9/5)(1)+32=
We move all terms to the left:
f-((9/5)(1)+32)=0
We add all the numbers together, and all the variables
f-((+9/5)1+32)=0
We multiply all the terms by the denominator
f*5)1+32)-((+9=0
Wy multiply elements
5f^2+9=0
a = 5; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·5·9
Δ = -180
Delta is less than zero, so there is no solution for the equation

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