f=3/2(n-90)

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Solution for f=3/2(n-90) equation: 


x in (-oo:+oo)

f = (3/2)*(n-90) // - (3/2)*(n-90)

f-((3/2)*(n-90)) = 0

(-3/2)*(n-90)+f = 0

f-3/2*(n-90) = 0

f-3/2*(n-90) = 0

f-3/2*n+135 = 0

f-3/2*n+135 = 0

x belongs to the empty set

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