fn=(n+1)f

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Solution for fn=(n+1)f equation:


Simplifying
fn = (n + 1) * f

Reorder the terms:
fn = (1 + n) * f

Reorder the terms for easier multiplication:
fn = f(1 + n)
fn = (1 * f + n * f)
fn = (1f + fn)

Add '-1fn' to each side of the equation.
fn + -1fn = 1f + fn + -1fn

Combine like terms: fn + -1fn = 0
0 = 1f + fn + -1fn

Combine like terms: fn + -1fn = 0
0 = 1f + 0
0 = 1f

Solving
0 = 1f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '-1f' to each side of the equation.
0 + -1f = 1f + -1f
Remove the zero:
-1f = 1f + -1f

Combine like terms: 1f + -1f = 0
-1f = 0

Divide each side by '-1'.
f = 0

Simplifying
f = 0

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