g(-8)=(-8+2)/3

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Solution for g(-8)=(-8+2)/3 equation: 



g(-8)=(-8+2)/3

We move all terms to the left:

g(-8)-((-8+2)/3)=0

We add all the numbers together, and all the variables

g(-8)-((-6)/3)=0

We multiply parentheses

-8g-((-6)/3)=0

We multiply all the terms by the denominator


-8g*3)-((-6)=0

Wy multiply elements

-24g^2=0

a = -24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-24)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$g=\frac{-b}{2a}=\frac{0}{-48}=0$

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