g(17-3g)=-102

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Solution for g(17-3g)=-102 equation:



g(17-3g)=-102
We move all terms to the left:
g(17-3g)-(-102)=0
We add all the numbers together, and all the variables
g(-3g+17)-(-102)=0
We add all the numbers together, and all the variables
g(-3g+17)+102=0
We multiply parentheses
-3g^2+17g+102=0
a = -3; b = 17; c = +102;
Δ = b2-4ac
Δ = 172-4·(-3)·102
Δ = 1513
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{1513}}{2*-3}=\frac{-17-\sqrt{1513}}{-6} $
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{1513}}{2*-3}=\frac{-17+\sqrt{1513}}{-6} $

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