g(b+1)=9x-3

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Solution for g(b+1)=9x-3 equation: 


Simplifying
g(b + 1) = 9x + -3

Reorder the terms:
g(1 + b) = 9x + -3
(1 * g + b * g) = 9x + -3

Reorder the terms:
(bg + 1g) = 9x + -3
(bg + 1g) = 9x + -3

Reorder the terms:
bg + 1g = -3 + 9x

Solving
bg + 1g = -3 + 9x

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1g' to each side of the equation.
bg + 1g + -1g = -3 + -1g + 9x

Combine like terms: 1g + -1g = 0
bg + 0 = -3 + -1g + 9x
bg = -3 + -1g + 9x

Divide each side by 'g'.
b = -3g-1 + -1 + 9g-1x

Simplifying
b = -3g-1 + -1 + 9g-1x

Reorder the terms:
b = -1 + -3g-1 + 9g-1x

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