g-3=12/g=15

Solution for g-3=12/g=15 equation:

g-3=12/g=15

We move all terms to the left:

g-3-(12/g)=0


Domain of the equation: g)!=0

g!=0/1

g!=0

g∈R


We add all the numbers together, and all the variables

g-(+12/g)-3=0

We get rid of parentheses

g-12/g-3=0

We multiply all the terms by the denominator


g*g-3*g-12=0

We add all the numbers together, and all the variables

-3g+g*g-12=0

Wy multiply elements

g^2-3g-12=0

a = 1; b = -3; c = -12;
Δ = b2-4ac
Δ = -32-4·1·(-12)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{57}}{2*1}=\frac{3-\sqrt{57}}{2}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{57}}{2*1}=\frac{3+\sqrt{57}}{2}
$