g0+g1+g2=(1+g2)

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Solution for g0+g1+g2=(1+g2) equation: 



g0+g1+g2=(1+g2)

We move all terms to the left:

g0+g1+g2-((1+g2))=0

We add all the numbers together, and all the variables

-((+g^2+1))+g0+g1+g2=0

We add all the numbers together, and all the variables

g^2-((+g^2+1))+2g=0



We calculate terms in parentheses: -((+g^2+1)), so:

(+g^2+1)

We get rid of parentheses

g^2+1

Back to the equation:

-(g^2+1)



We add all the numbers together, and all the variables

g^2+2g-(g^2+1)=0

We get rid of parentheses

g^2-g^2+2g-1=0

We add all the numbers together, and all the variables

2g-1=0

We move all terms containing g to the left, all other terms to the right

2g=1

g=1/2

g=1/2

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