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g2+8g+3=0
We add all the numbers together, and all the variables
g^2+8g+3=0
a = 1; b = 8; c = +3;
Δ = b2-4ac
Δ = 82-4·1·3
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{13}}{2*1}=\frac{-8-2\sqrt{13}}{2} $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{13}}{2*1}=\frac{-8+2\sqrt{13}}{2} $
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