g2=23g=6

Solution for g2=23g=6 equation:

g2=23g=6

We move all terms to the left:

g2-(23g)=0

We add all the numbers together, and all the variables

g^2-23g=0

a = 1; b = -23; c = 0;
Δ = b2-4ac
Δ = -232-4·1·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-23}{2*1}=\frac{0}{2}
=0
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+23}{2*1}=\frac{46}{2}
=23
$