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g2=9/12
We move all terms to the left:
g2-(9/12)=0
We add all the numbers together, and all the variables
g2-(+9/12)=0
We add all the numbers together, and all the variables
g^2-(+9/12)=0
We get rid of parentheses
g^2-9/12=0
We multiply all the terms by the denominator
g^2*12-9=0
Wy multiply elements
12g^2-9=0
a = 12; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·12·(-9)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*12}=\frac{0-12\sqrt{3}}{24} =-\frac{12\sqrt{3}}{24} =-\frac{\sqrt{3}}{2} $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*12}=\frac{0+12\sqrt{3}}{24} =\frac{12\sqrt{3}}{24} =\frac{\sqrt{3}}{2} $
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