g=2+2+3+7+((g-7)/2)+1

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Solution for g=2+2+3+7+((g-7)/2)+1 equation: 



g=2+2+3+7+((g-7)/2)+1

We move all terms to the left:

g-(2+2+3+7+((g-7)/2)+1)=0

We multiply all the terms by the denominator


g*2)+1)-(2+2+3+7+((g-7)=0

Wy multiply elements

2g^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$g=\frac{-b}{2a}=\frac{0}{4}=0$

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