h(-8)=5/4(4-t)

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Solution for h(-8)=5/4(4-t) equation: 



(-8)=5/4(4-H)

We move all terms to the left:

(-8)-(5/4(4-H))=0



Domain of the equation: 4(4-H))!=0

H∈R



We add all the numbers together, and all the variables

-(5/4(-1H+4))+(-8)=0

We add all the numbers together, and all the variables

-(5/4(-1H+4))-8=0

We multiply all the terms by the denominator


-(5-8*4(-1H+4))=0



We calculate terms in parentheses: -(5-8*4(-1H+4)), so:

5-8*4(-1H+4)

determiningTheFunctionDomain
-8*4(-1H+4)+5

Wy multiply elements

-32H(-+5

We use the square of the difference formula

-32H(-5

Back to the equation:

-(-32H(-5)





We calculate terms in parentheses: -(-32H(-5), so:

-32H(-5





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-32H(-5





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-32H(-5





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