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h(2)=4.2(2)-3
We move all terms to the left:
h(2)-(4.2(2)-3)=0
We add all the numbers together, and all the variables
h2-(1.22)=0
We add all the numbers together, and all the variables
h^2-1.22=0
a = 1; b = 0; c = -1.22;
Δ = b2-4ac
Δ = 02-4·1·(-1.22)
Δ = 4.88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{4.88}}{2*1}=\frac{0-\sqrt{4.88}}{2} =-\frac{\sqrt{}}{2} $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{4.88}}{2*1}=\frac{0+\sqrt{4.88}}{2} =\frac{\sqrt{}}{2} $
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