h(4+6h)=h

Solution for h(4+6h)=h equation:

h(4+6h)=h

We move all terms to the left:

h(4+6h)-(h)=0

We add all the numbers together, and all the variables

h(6h+4)-h=0

We add all the numbers together, and all the variables

-1h+h(6h+4)=0

We multiply parentheses

6h^2-1h+4h=0

We add all the numbers together, and all the variables

6h^2+3h=0

a = 6; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·6·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*6}=\frac{-6}{12}
=-1/2
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*6}=\frac{0}{12}
=0
$