h(h+2h)=300

Solution for h(h+2h)=300 equation:

h(h+2h)=300

We move all terms to the left:

h(h+2h)-(300)=0

We add all the numbers together, and all the variables

h(+3h)-300=0

We multiply parentheses

3h^2-300=0

a = 3; b = 0; c = -300;
Δ = b2-4ac
Δ = 02-4·3·(-300)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*3}=\frac{-60}{6}
=-10
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*3}=\frac{60}{6}
=10
$