If it's not what You are looking for type in the equation solver your own equation and let us solve it.
h(h+6)=0
We multiply parentheses
h^2+6h=0
a = 1; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·1·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*1}=\frac{-12}{2} =-6 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*1}=\frac{0}{2} =0 $
| 28=y/5-9 | | (5x-1)+(2x+49)+90=180 | | (m+2)(m-7)=0 | | 7(p+3)+9=(5p-2)-3p | | 1/3z-2=5-8/3z | | 5x+x+4=-56 | | 5x+x+4=156 | | n²-3n-208=0 | | (m+2)(m−7)=0 | | n-3n-208=0 | | x=-5-362 | | n2-3n-208=0 | | n+9/3=-2 | | 5x2-12=17x | | (d+4)(d+1)=0 | | 6x+4+5x=59 | | x3-2x2-6x+72=0 | | 7-2b=-9 | | 8+4x=4x | | 2×(w-2)=16 | | 3(t-10)=18 | | (s-2)(s+6)=0 | | x/8=41 | | 4(n+16)=12 | | 12=-5q+2 | | -3(q+17)=-18 | | 4y-16.31=53.1 | | 2x-20=24 | | 7+11u=-1+u+6u | | 12-5d=-9d | | 11-3x=-75 | | 3n=-n+8 |