h*h+4h-3h=2h*2h

Solution for h*h+4h-3h=2h*2h equation:

h*h+4h-3h=2h*2h

We move all terms to the left:

h*h+4h-3h-(2h*2h)=0

We add all the numbers together, and all the variables

h*h+4h-3h-(+2h*2h)=0

We add all the numbers together, and all the variables

h+h*h-(+2h*2h)=0

Wy multiply elements

h^2+h-(+2h*2h)=0

We get rid of parentheses

h^2+h-2h*2h=0

Wy multiply elements

h^2-4h^2+h=0

We add all the numbers together, and all the variables

-3h^2+h=0

a = -3; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-3)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-3}=\frac{-2}{-6}
=1/3
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-3}=\frac{0}{-6}
=0
$