h+(h-2+3)+(h-2)=20

Solution for h+(h-2+3)+(h-2)=20 equation:

Simplifying
h + (h + -2 + 3) + (h + -2) = 20

Reorder the terms:
h + (-2 + 3 + h) + (h + -2) = 20

Combine like terms: -2 + 3 = 1
h + (1 + h) + (h + -2) = 20

Remove parenthesis around (1 + h)
h + 1 + h + (h + -2) = 20

Reorder the terms:
h + 1 + h + (-2 + h) = 20

Remove parenthesis around (-2 + h)
h + 1 + h + -2 + h = 20

Reorder the terms:
1 + -2 + h + h + h = 20

Combine like terms: 1 + -2 = -1
-1 + h + h + h = 20

Combine like terms: h + h = 2h
-1 + 2h + h = 20

Combine like terms: 2h + h = 3h
-1 + 3h = 20

Solving
-1 + 3h = 20

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 3h = 20 + 1

Combine like terms: -1 + 1 = 0
0 + 3h = 20 + 1
3h = 20 + 1

Combine like terms: 20 + 1 = 21
3h = 21

Divide each side by '3'.
h = 7

Simplifying
h = 7