h+2/3(h+4)=34

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Solution for h+2/3(h+4)=34 equation:



h+2/3(h+4)=34
We move all terms to the left:
h+2/3(h+4)-(34)=0
Domain of the equation: 3(h+4)!=0
h∈R
We multiply all the terms by the denominator
h*3(h+4)-34*3(h+4)+2=0
Wy multiply elements
3h^2(h-102h(h+2=0

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