h-(-1h-1)/2h=-1

Solution for h-(-1h-1)/2h=-1 equation:

h-(-1h-1)/2h=-1

We move all terms to the left:

h-(-1h-1)/2h-(-1)=0


Domain of the equation: 2h!=0

h!=0/2

h!=0

h∈R


We add all the numbers together, and all the variables

h-(-1h-1)/2h+1=0

We multiply all the terms by the denominator


h*2h-(-1h-1)+1*2h=0

Wy multiply elements

2h^2-(-1h-1)+2h=0

We get rid of parentheses

2h^2+1h+2h+1=0

We add all the numbers together, and all the variables

2h^2+3h+1=0

a = 2; b = 3; c = +1;
Δ = b2-4ac
Δ = 32-4·2·1
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-1}{2*2}=\frac{-4}{4}
=-1
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+1}{2*2}=\frac{-2}{4}
=-1/2
$