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h/2(3-h)-6=-5h
We move all terms to the left:
h/2(3-h)-6-(-5h)=0
Domain of the equation: 2(3-h)!=0We add all the numbers together, and all the variables
h∈R
h/2(-1h+3)-(-5h)-6=0
We get rid of parentheses
h/2(-1h+3)+5h-6=0
We multiply all the terms by the denominator
h+5h*2(-1h+3)-6*2(-1h+3)=0
Wy multiply elements
10h^2(--12h(-+h=0
We use the square of the difference formula
10h^2(+12h(-h=0
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