h/4=(-20)/16

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Solution for h/4=(-20)/16 equation: 



h/4=(-20)/16

We move all terms to the left:

h/4-((-20)/16)=0

We calculate fractions


16h^2/()+()/()=0

We add all the numbers together, and all the variables

16h^2/()+1=0

We multiply all the terms by the denominator


16h^2+1*()=0

We add all the numbers together, and all the variables

16h^2=0

a = 16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·16·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$h=\frac{-b}{2a}=\frac{0}{32}=0$

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