h/5h+2(11-h)=-5

Solution for h/5h+2(11-h)=-5 equation:

h/5h+2(11-h)=-5

We move all terms to the left:

h/5h+2(11-h)-(-5)=0


Domain of the equation: 5h!=0

h!=0/5

h!=0

h∈R


We add all the numbers together, and all the variables

h/5h+2(-1h+11)-(-5)=0

We add all the numbers together, and all the variables

h/5h+2(-1h+11)+5=0

We multiply parentheses

h/5h-2h+22+5=0

We multiply all the terms by the denominator


h-2h*5h+22*5h+5*5h=0

Wy multiply elements

-10h^2+h+110h+25h=0

We add all the numbers together, and all the variables

-10h^2+136h=0

a = -10; b = 136; c = 0;
Δ = b2-4ac
Δ = 1362-4·(-10)·0
Δ = 18496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{18496}=136$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(136)-136}{2*-10}=\frac{-272}{-20}
=13+3/5
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(136)+136}{2*-10}=\frac{0}{-20}
=0
$