h2=0.36h

Solution for h2=0.36h equation:

h2=0.36h

We move all terms to the left:

h2-(0.36h)=0

We add all the numbers together, and all the variables

h2-(+0.36h)=0

We add all the numbers together, and all the variables

h^2-(+0.36h)=0

We get rid of parentheses

h^2-0.36h=0

a = 1; b = -0.36; c = 0;
Δ = b2-4ac
Δ = -0.362-4·1·0
Δ = 0.1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.36)-\sqrt{0.1296}}{2*1}=\frac{0.36-\sqrt{0.1296}}{2}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.36)+\sqrt{0.1296}}{2*1}=\frac{0.36+\sqrt{0.1296}}{2}
$