If it's not what You are looking for type in the equation solver your own equation and let us solve it.
h2=100
We move all terms to the left:
h2-(100)=0
We add all the numbers together, and all the variables
h^2-100=0
a = 1; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·1·(-100)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*1}=\frac{-20}{2} =-10 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*1}=\frac{20}{2} =10 $
| 2x+31=2x+-31 | | x2=-8 | | 5+2j=-3 | | j2+42=0 | | 2/7x-2/5x=8 | | X^(2)=(x/4)+(48/1) | | 183=8s+3/2s+12 | | s2+39=39 | | 15=40a | | x*2+x/4=90 | | k-434=814 | | u2+97=9 | | (-8/6)/(6x)=(10/6)/(2x+6/8) | | 22-3x=2(×+6) | | 11x-1=12x+13+24 | | -2x-11=6 | | -2=x-116 | | 12x=1/16 | | 8x+4x+3+7=3x+3+8x | | 5^{2x+3}=18 | | (3x-33)=90 | | 17x+8=12x-4+42 | | 6=d+2/4 | | 7x+x^2=29 | | 4x+8/3=3/16 | | 9d/4=-9 | | x/6+2.33333-3.5*1.2=23/5 | | 9/4d=-9 | | |3.2-1.054x|=2 | | 4/x-5=7x | | 3=d=9/4 | | 4+6(x-1)=1-6(x-8) |