h=(-16)(1.2)+(h-20.04)(1.2)+3

Solution for h=(-16)(1.2)+(h-20.04)(1.2)+3 equation:

h=(-16)(1.2)+(h-20.04)(1.2)+3

We move all terms to the left:

h-((-16)(1.2)+(h-20.04)(1.2)+3)=0

We multiply parentheses ..

h-((-19.2)+(h-20.04)(1.2)+3)=0


We calculate terms in parentheses: -((-19.2)+(h-20.04)(1.2)+3), so:

(-19.2)+(h-20.04)(1.2)+3

determiningTheFunctionDomain
(h-20.04)(1.2)+3+(-19.2)

We add all the numbers together, and all the variables

(h-20.04)(1.2)-16.2

We multiply parentheses ..

(+1.2h-24.048)-16.2

We add all the numbers together, and all the variables

(1.2h-24.048)-16.2

We get rid of parentheses

1.2h-24.048-16.2

We add all the numbers together, and all the variables

1.2h-40.248

Back to the equation:

-(1.2h-40.248)


We get rid of parentheses

h-1.2h+40.248=0

We add all the numbers together, and all the variables

-0.2h+40.248=0

We move all terms containing h to the left, all other terms to the right

-0.2h=-40.248

h=-40.248/-0.2

h=201+0.048/0.2