h=-(60)2+3(60)+10

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Solution for h=-(60)2+3(60)+10 equation: 



h=-(60)2+3(60)+10

We move all terms to the left:

h-(-(60)2+3(60)+10)=0

We add all the numbers together, and all the variables

h-(-232)=0

We add all the numbers together, and all the variables

h+232=0

We move all terms containing h to the left, all other terms to the right

h=-232

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