h=4((h+2)/2)

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Solution for h=4((h+2)/2) equation: 



h=4((h+2)/2)

We move all terms to the left:

h-(4((h+2)/2))=0

We multiply all the terms by the denominator


h*2))-(4((h+2)=0

Wy multiply elements

2h^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$h=\frac{-b}{2a}=\frac{0}{4}=0$

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