i(2)=((3i+2)-11)

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Solution for i(2)=((3i+2)-11) equation: 


Simplifying
i(2) = ((3i + 2) + -11)

Reorder the terms for easier multiplication:
2i = ((3i + 2) + -11)

Reorder the terms:
2i = ((2 + 3i) + -11)

Remove parenthesis around (2 + 3i)
2i = (2 + 3i + -11)

Reorder the terms:
2i = (2 + -11 + 3i)

Combine like terms: 2 + -11 = -9
2i = (-9 + 3i)

Remove parenthesis around (-9 + 3i)
2i = -9 + 3i

Solving
2i = -9 + 3i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-3i' to each side of the equation.
2i + -3i = -9 + 3i + -3i

Combine like terms: 2i + -3i = -1i
-1i = -9 + 3i + -3i

Combine like terms: 3i + -3i = 0
-1i = -9 + 0
-1i = -9

Divide each side by '-1'.
i = 9

Simplifying
i = 9

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