i(4-8i)(7-4i)=0

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Solution for i(4-8i)(7-4i)=0 equation: 



i(4-8i)(7-4i)=0

We add all the numbers together, and all the variables

i(-8i+4)(-4i+7)=0

We multiply parentheses ..

i(+32i^2-56i-16i+28)=0

We multiply parentheses

32i^3-56i^2-16i^2+28i=0

We do not support eipression: i^3

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