i(z+1)=3z-2

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Solution for i(z+1)=3z-2 equation:


Simplifying
i(z + 1) = 3z + -2

Reorder the terms:
i(1 + z) = 3z + -2
(1 * i + z * i) = 3z + -2
(1i + iz) = 3z + -2

Reorder the terms:
1i + iz = -2 + 3z

Solving
1i + iz = -2 + 3z

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
2 + 1i + iz + -3z = -2 + 3z + 2 + -3z

Reorder the terms:
2 + 1i + iz + -3z = -2 + 2 + 3z + -3z

Combine like terms: -2 + 2 = 0
2 + 1i + iz + -3z = 0 + 3z + -3z
2 + 1i + iz + -3z = 3z + -3z

Combine like terms: 3z + -3z = 0
2 + 1i + iz + -3z = 0

The solution to this equation could not be determined.

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