i2x+1i/3=8

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Solution for i2x+1i/3=8 equation:



2I+1/3=8
We move all terms to the left:
2I+1/3-(8)=0
determiningTheFunctionDomain 2I-8+1/3=0
We multiply all the terms by the denominator
2I*3+1-8*3=0
We add all the numbers together, and all the variables
2I*3-23=0
Wy multiply elements
6I-23=0
We move all terms containing I to the left, all other terms to the right
6I=23
I=23/6
I=3+5/6

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