i2x+3i=15

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Solution for i2x+3i=15 equation: 



2I+3=15

We move all terms to the left:

2I+3-(15)=0

We add all the numbers together, and all the variables

2I-12=0

We move all terms containing I to the left, all other terms to the right

2I=12

I=12/2

I=6

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