in(x+4)-in(x-2)=in(13)

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Solution for in(x+4)-in(x-2)=in(13) equation:


Simplifying
in(x + 4) + -1in(x + -2) = in(13)

Reorder the terms:
in(4 + x) + -1in(x + -2) = in(13)
(4 * in + x * in) + -1in(x + -2) = in(13)
(4in + inx) + -1in(x + -2) = in(13)

Reorder the terms:
4in + inx + -1in(-2 + x) = in(13)
4in + inx + (-2 * -1in + x * -1in) = in(13)
4in + inx + (2in + -1inx) = in(13)

Reorder the terms:
4in + 2in + inx + -1inx = in(13)

Combine like terms: 4in + 2in = 6in
6in + inx + -1inx = in(13)

Combine like terms: inx + -1inx = 0
6in + 0 = in(13)
6in = in(13)

Reorder the terms for easier multiplication:
6in = 13in

Solving
6in = 13in

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-13in' to each side of the equation.
6in + -13in = 13in + -13in

Combine like terms: 6in + -13in = -7in
-7in = 13in + -13in

Combine like terms: 13in + -13in = 0
-7in = 0

Divide each side by '-7'.
in = 0

Simplifying
in = 0

The solution to this equation could not be determined.

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