in(x-2)+in(2x+1)=5

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Solution for in(x-2)+in(2x+1)=5 equation: 


Simplifying
in(x + -2) + in(2x + 1) = 5

Reorder the terms:
in(-2 + x) + in(2x + 1) = 5
(-2 * in + x * in) + in(2x + 1) = 5
(-2in + inx) + in(2x + 1) = 5

Reorder the terms:
-2in + inx + in(1 + 2x) = 5
-2in + inx + (1 * in + 2x * in) = 5
-2in + inx + (1in + 2inx) = 5

Reorder the terms:
-2in + 1in + inx + 2inx = 5

Combine like terms: -2in + 1in = -1in
-1in + inx + 2inx = 5

Combine like terms: inx + 2inx = 3inx
-1in + 3inx = 5

Solving
-1in + 3inx = 5

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Reorder the terms:
-5 + -1in + 3inx = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + -1in + 3inx = 0

The solution to this equation could not be determined.

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