iz+2conj(z)=6-i

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Solution for iz+2conj(z)=6-i equation:


Simplifying
iz + 2conj(z) = 6 + -1i

Multiply cjno * z
iz + 2cjnoz = 6 + -1i

Reorder the terms:
2cjnoz + iz = 6 + -1i

Solving
2cjnoz + iz = 6 + -1i

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1iz' to each side of the equation.
2cjnoz + iz + -1iz = 6 + -1i + -1iz

Combine like terms: iz + -1iz = 0
2cjnoz + 0 = 6 + -1i + -1iz
2cjnoz = 6 + -1i + -1iz

Divide each side by '2jnoz'.
c = 3j-1n-1o-1z-1 + -0.5ij-1n-1o-1z-1 + -0.5ij-1n-1o-1

Simplifying
c = 3j-1n-1o-1z-1 + -0.5ij-1n-1o-1z-1 + -0.5ij-1n-1o-1

Reorder the terms:
c = -0.5ij-1n-1o-1 + -0.5ij-1n-1o-1z-1 + 3j-1n-1o-1z-1

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