j+2(j+1)-3(j-4)=20

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Solution for j+2(j+1)-3(j-4)=20 equation:


Simplifying
j + 2(j + 1) + -3(j + -4) = 20

Reorder the terms:
j + 2(1 + j) + -3(j + -4) = 20
j + (1 * 2 + j * 2) + -3(j + -4) = 20
j + (2 + 2j) + -3(j + -4) = 20

Reorder the terms:
j + 2 + 2j + -3(-4 + j) = 20
j + 2 + 2j + (-4 * -3 + j * -3) = 20
j + 2 + 2j + (12 + -3j) = 20

Reorder the terms:
2 + 12 + j + 2j + -3j = 20

Combine like terms: 2 + 12 = 14
14 + j + 2j + -3j = 20

Combine like terms: j + 2j = 3j
14 + 3j + -3j = 20

Combine like terms: 3j + -3j = 0
14 + 0 = 20
14 = 20

Solving
14 = 20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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